Question

If 2 is a zero of polynomial 4y^2-6y-k, find the value of k. Also, find the
other zero. Answer this to become brainalist fast

Answer 1

Answer:

-1/2

Step-by-step explanation:

Given f(x) = 4y^2 - 6y - k.

Given that 2 is a zero of the polynomial. f(2) = 0.

= > 4(2)^2 - 6(2) - k = 0

= > 16 - 12 - k = 0

= > 4 - k = 0

= > k = 4.

Therefore the value of k = 4.

Now,

We need to Substitute the value of k in the given equation.

= > 4y^2 - 6y - k = 0

= > 4y^2 - 8y + 2y - 4 = 0

= > 4y(y - 2) + 2(y - 2) = 0

= > (4y + 2)(y - 2) = 0

= > y = -1/2, y = 2.

Therefore the other zero is -1/2.

Hope this helps!