if 2 is a zero of polynomial f(x)=ax²-3(a-1)x-1;then find the value of a
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the..f(2)=a(2)^2-3a+1(x-1)
=4a-3a+2-1
=a+1
a=-1.
=4a-3a+2-1
=a+1
a=-1.
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Given 2 is a zero of polynomial f(x).
So, x = 2.
By Factor theorem,
f(x) = ax² - 3 ( a - 1 )x - 1
f(2) = a(2)² - 3( a - 1 )2 - 1 = 0
⇒ 4a - ( 3a - 3 )2 - 1 = 0
⇒ 4a - 6a + 6 - 1 = 0
⇒ -2a + 5 = 0
⇒ -2a = -5
⇒ a = -5 / -2
⇒ a = 5 / 2
So, if the value of a is 5/2 then 2 will be a zero of f(x).
So, x = 2.
By Factor theorem,
f(x) = ax² - 3 ( a - 1 )x - 1
f(2) = a(2)² - 3( a - 1 )2 - 1 = 0
⇒ 4a - ( 3a - 3 )2 - 1 = 0
⇒ 4a - 6a + 6 - 1 = 0
⇒ -2a + 5 = 0
⇒ -2a = -5
⇒ a = -5 / -2
⇒ a = 5 / 2
So, if the value of a is 5/2 then 2 will be a zero of f(x).
Anonymous:
Thanks
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