If 2 is a zero of polynomial g(z)=pz square -3(p-1)z-1 then find the value of p..
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Answered by
21
2 is the zero of g(z) = Pz² -3(P -1)z -1 ,
so, put z = 2 in g(z) and equate to zero .
g(2) = P(2)² -3(P -1)(2) -1 = 0
4P -6( P - 1) -1 = 0
4P - 6P + 6 -1 = 0
-2P + 5 = 0
P = 5/2
so, put z = 2 in g(z) and equate to zero .
g(2) = P(2)² -3(P -1)(2) -1 = 0
4P -6( P - 1) -1 = 0
4P - 6P + 6 -1 = 0
-2P + 5 = 0
P = 5/2
tanu66:
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Answered by
11
Hey !
Given
2 is the zero of g(z) = Pz² -3(P -1)z -1
Lets pyt the value z = 2 in the equation :-
p(2)² -3(p -1)(2) -1 = 0
4p -6( p - 1) -1 = 0
4p - 6p + 6 -1 = 0
-2p+ 5 = 0
5 = 2p
p = 5/2
Given
2 is the zero of g(z) = Pz² -3(P -1)z -1
Lets pyt the value z = 2 in the equation :-
p(2)² -3(p -1)(2) -1 = 0
4p -6( p - 1) -1 = 0
4p - 6p + 6 -1 = 0
-2p+ 5 = 0
5 = 2p
p = 5/2
thank you
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