Question

If 2 is a zero of polynomial p(x)=ax^2-3x(a-1)-1, then find the value of a

Answer 1

Answer:

5

Step-by-step explanation:

Answer 2

if 2 is a zero of polynomial p (x)

$ax \times 2 - 3x{a - 1} - 1 = 0$

$a \times 2 \times 2 - 3 \times 2{a - 1} - 1 = 0$

$4a - 6a + 6 - 1 = 0$

$4a - 6a + 5 = 0$

$- 2a + 5 = 0$

$- 2a = 0 - 5$

$a = \frac{ - 5}{ - 2}$

$a = \frac{5}{2}$

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