Question

if 2 is a zero of polynomial p(x)=ax2 -3(a+2)-4 then the value of a is ​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{Solution:-}}}}}}$.

➡Given Equations :-

✴$\:p(x)\:=\:ax^2-3(a+2)-4$.

➡Find Here :-

✴$\:Value\:Of\:a$.

$\large{\underline{\underline{\mathfrak{\green{\sf{Explanation:-}}}}}}$.

We know, if 2 is a zero of this equations , so,

x=2, satisfies of this equations .

➡So, Keep x=2 ,

$\implies\:p(2)\:=a*2^2-3(a+2)-4\:=\:0$.

$\implies\:4a^2-3a-10\:=\:0$.

$\implies\:4a^2-8a+5a-10\:=\:0$.

$\implies\:4a(a-8)+5(a-2)\:=\:0$.

$\implies\:(4a+5)(a-8)\:=0$.

$\implies\:(4a+5)\:=0\:,Or\:(a-8)\:=0$.

$\implies\:a\:=\frac{-5}{4}\:Or\:a\:=\:8$.

____________________

Answer 2

The value of a = 10

Given :

2 is a zero of polynomial p(x) = ax² - 3(a + 2) - 4

To find :

The value of a

Solution :

Step 1 of 2 :

Write down the given polynomial

Here the given polynomial is

p(x) = ax² - 3(a + 2) - 4

Step 2 of 2 :

Find the value of a

Since 2 is a zero of polynomial p(x) = ax² - 3(a + 2) - 4

$\displaystyle \sf{ \therefore \: p(2) = 0 }$

$\displaystyle \sf{ \implies a \times {2}^{2} - 3(a + 2) - 4 = 0}$

$\displaystyle \sf{ \implies 4a - 3a - 6- 4 = 0}$

$\displaystyle \sf{ \implies a - 10 = 0}$

$\displaystyle \sf{ \implies a = 10}$

Hence the required value of a = 10

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ if polynomial p(t)=t⁴-t³+t²+6,then find p(-1)

https://brainly.in/question/3539645

2. Find the value of the polynomial 2x + 5 at x = – 3

https://brainly.in/question/50335429

#SPJ3