Question

If 2 is a zero of polynomial px2+(p+3)x+6 then what is the value of p​

Answer 1

Answer:

p = -2

Step-by-step explanation:

px²+(p+3)x+6

Substituting 2 at place of x,

p(2)² + (p+3)2 + 6 = 0

=> 4p + 2p + 6 + 6 = 0

=> 6p + 12 = 0

=> 6p = -12

=> p = -12/6

=> p = -2