Question

if 2 is a zero of polynomial x^2-kx+8then,k=​

Answer 1

Answer:

Let P(x)=x²-kx+8

since,2 is a zero of polynomial p(x)

so,p(2)=0

2²-k×2+8=0

4-2k+8=0

12-2k=0

2k=12

k=6