If 2 is a zero of polynomial4 2 − 6 + ,find the value of k
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Answer:
k = 4
Step-by-step explanation:
Given f(x)=4y^2 - 6y - k
Given that 2 is the zero of the polynomial .
f(2) = 0
= 4(2)^2 - 6 (2) - k = 0
= 16 -12 - k = 0
= 4 - k = 0
= k = 4
Therefore the value of k is 4
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