Question

if 2 is a zero of the polynomial p(x)=x^3-2 kx^2+kx-1 then find the value of k

Answer 1

Answer:

given that,

p(2)=0

${x}^{3} - 2k {x}^{2} + kx - 1 \\ substitute \:2 \: in \: p(x) \\ {2}^{3} - 2k( {2})^{2} + k(2) - 1 = 0 \\ 8 - 8k + 2k - 1 = 0 \\ ( - 6k) + 7 = 0 \\ - 6k = - 7 \\ 6k = 7 \\ k = \frac{7}{6}$

I hope it is helpful..................

Answer 2

x³-2kx²+kx-1

x=2

2³-2k2²+k2-1=0

8-k8+2k-1=0

-6k=-8+1

-6k=-7

k=7/6