Question

if 2 is a zero of the polynomial p(x)=x^3-2kx^2+kx-1​

Answer 1

Answer:

Step-by-step explanation:

p(x) = x³- 2kx² + kx - 1

p(2) = 2³ - 2k × 2² +k × 2 -1

p(2) = 8- 8k+2k - 1

p(2) = 7- 6k

Answer 2

Answer:

p(x)=2*3-2k2*2+k2-1

=>6-4k*2+k=0

=&6-8k+k=0

=>8k+k=-6

=>9k=-6

=>k=-6/9

=>k=-2/3hope itchy will help u

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