Math, asked by ananditasingh4327, 20 days ago

if (-2)is a zero of the polynomial p(x)=x^3+ax^2-4x-12,then find the value of a​

Answers

Answered by satyendrasddubey
1

Answer:

3now the remainder of first polynomial is 54+9a = 54+9(-3)=54-27= 27Step-by-step ...

Answered by shivamtiwari3314
0

Answer:

Since, it is given that

3

and −

3

are the zeroes of the polynomial f(x)=x

3

−4x

2

−3x+12, therefore, (x−

3

) and (x+

3

) are also the zeroes of the given polynomial. Now, consider the product of zeroes as follows:

(x−

3

)(x+

3

)

=(x)

2

−(

3

)

2

(∵a

2

−b

2

=(a+b)(a−b))

=x

2

−3

We now divide x

3

−4x

2

−3x+12 by (x

2

−3) as shown in the above image:

From the division, we observe that the quotient is x−4 and the remainder is 0.

Since x−4 is the quotient,

Hence, the third zero of f(x)=x

3

−4x

2

−3x+12 is 4.

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