Question

if 2 is a zero of the polynomial x^3-3x^2+4x+k then find the valve of k​

Answer 1

Answer:

Given:

2 is a zero of polynomial of x^3 - 3x^2 +4x +k

To Find:

find the value of k in given equation.

Proof:

x^3 - 3x^2 +4x + k = 0

[2]^3 - 3[2]^2 + 4[2] + k = 0

8 - 12 +8 + k = 0

k = -4

Answer 2

${x}^{3} - 3 {x}^{2} + 4x + k = 0 \\ \\ x = 2 \\ \\ {2}^{3} - 3 \times {2}^{2} + 4 \times 2 + k = 0 \\ \\ 8 - 12 + 8 + k = 0 \\ \\ 4 + k = 0 \\ \\ \pink{ \huge{k = - 4}}$