If 2 is a zero of the polynomial x2-3x+k,then find k and the other zero
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given
quadratic
f(X) =
x²-3x+k
if X = 2 is zero of f(X)
then f(2) should be zero
f(2) = (2)²-3*2+k = 0
=> 4-6 +k = 0
=> k = 2
now f(X) = x²-3x+2
= x²-2x-x +2
= x(x-2)-1(x-2)
= (x-2)(x-1)
thus another factor of f(X) is x-1
so zero will be X = 1
quadratic
f(X) =
x²-3x+k
if X = 2 is zero of f(X)
then f(2) should be zero
f(2) = (2)²-3*2+k = 0
=> 4-6 +k = 0
=> k = 2
now f(X) = x²-3x+2
= x²-2x-x +2
= x(x-2)-1(x-2)
= (x-2)(x-1)
thus another factor of f(X) is x-1
so zero will be X = 1
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