Question

If 2 is a zero of the polynomial x²-kx+8, then k=​

Answer 1

Step-by-step explanation:

x^2-kx+8

one zero is 2

put 2 at place of x in the equation

2^2-2k+8=0

4-2k+8=0

12-2k=0

-2k=-12

2k=12

k=6

hope its helpful

thanks

Answer 2

Answer:

x² - kx + 8

one zero is 2

put 2 at place of x in the equation

2² - 2k + 8 = 0

4 - 2k + 8 = 0

12 - 2k = 0

-2k = -12

2k = 12

k = 6

Step-by-step explanation:

Hope this helps you :)