If 2 is a zero of the polynomial x²-kx+8, then k=
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Answer:
put x=2 in given polynomial.
then, 2^2 -k(2)+8 =0
4-2k+8=0
2k=12
k=6
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it means the value of x=2
2×2-k×2+8=0
4-2k+8=0
12-2k=0
-2k=-12
k=-12/-2
k=6
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