Question

If 2 is a zero of x cube minus 6 x square + px - 6 then value of the p is

Answer 1

Given :

• 2 is a zero of x³ - 6x² + px - 6

To Find :

• The value of p

Solution :

2 is a zero of x³ - 6x² + px - 6

→ x = 2

Putting the value of x in x³ - 6x² + px - 6

x³ - 6x² + px - 6 = 0

→ 2³ + (6 × 2²) + (p × 2) - 6 = 0

→ 8 + 24 + 2p - 6 = 0

→ 26 + 2p = 0

→ 2p = - 26

→ p = - 26/2

→ p = - 13

So, the value of p is (-13)

Answer 2

Answer:

p = 11

Step-by-step explanation:

• f(x) = x³ - 6x² + px - 6
• If x = 2 is a Zero of the given Cubic Equation.
• So, for x = 2, f(x= 2) = 0

<x = 2 must satisfy the equation>

• Putting x = 2, we get:
• (2)³ - 6(2)² + p(2) - 6 = 0
• 8 - 24 + 2p - 6 = 0
• 2p = 22
• p = 11

Thanks!