Question

If 2 is added to the numerator and denominator it becomes 9/10 and if 3 is substracted from the numerator and denominator it becomes 4/5 find the fractions

by eliminating mathod
please answer me fast​

Answer 1

$\huge\underline\red{anwer}</p><p>$

Let the fraction be x/y

in the first case, when 2 is added to both

numerator and denomiantor,

X+2)/(y+2)-9/10

cross multiply ans solve it.

the equation will be 9y-10x=2. ..(1)

in the second case, when 3 is subtracted

from both numerator and denominator,

(x-3)/(y-3)=4/5

solve it

the equation will be, 5x-4y-3.(2)

now from equation 2, we can take the

value of y as (5x-3)/4.now substitute in

equation 1.

it will be 9/4(5x-3)-10x=2.

solve this equation and you will get the

value of x . use it to find the value of y.

I NEED ONE MORE BRAINLIST ANSWER THEN MY RANK UP PLEASE MARK AS BRAINLIST.

Answer 2

Answer :

›»› The fraction = 7/8

Given :

• If 2 is added to the numerator and denominator it becomes 9/10.
• If 3 is substracted from the numerator and denominator it becomes 4/5.

To Find :

• The fraction = ?

How To Find ?

❍ Here in the this question we have to find the fraction. So, firstly we have to assume the numerator be x and denominator be y, then our fraction will be x/y, after all this we will find the fraction on the basis of conditions given above and understand the steps to get our result of fraction.

Required Solution :

Let ,

The numerator be "x" and denominator "y"

Then the fraction be x/y

If 2 is added to numerator and denominator it becomes 9/10.

$\tt{:\implies \dfrac{x + 2}{y + 2} = \dfrac{9}{10} }$

$\tt{:\implies 10(x + 2) = 9(y + 2)}$

$\tt{:\implies 10x + 20 = 9y + 18}$

$\tt{:\implies 10x = 9y + 18 - 20}$

$\tt{:\implies x = \dfrac{9y - 2}{10}} \quad \quad\bf{ - - - - (1)}$

Again if 3 is subtracted from numerator and denominator it becomes 4/5.

$\tt{: \implies \dfrac{x - 3}{y - 3} = \dfrac{4}{5} }$

$\tt{: \implies 5(x - 3) = 4(y - 3)}$

$\tt{: \implies 5x - 15 = 4y - 12} \quad \quad\bf{ - - - - (2)}$

Put the value of x in equation (2)

$\tt{: \implies 5 \bigg( \dfrac{9y - 2}{10} \bigg) - 15 = 4y - 12}$

$\tt{: \implies \dfrac{9y - 2 - 5 \times 2}{2} = 4y - 12}$

$\tt{: \implies 9y - 2 - 30 = 2(4y - 12)}$

$\tt{: \implies 9y - 32 = 8y - 24}$

$\tt{: \implies 9y - 8y = - 24 + 32}$

$\tt{: \implies y = - 24 + 32}$

$\bf{: \implies y = 8}$

Now, put the value of y in equation (1)

$\tt{: \implies x = \dfrac{9 \times 8 - 2}{10} }$

$\tt{: \implies x = \dfrac{72 - 2}{10} }$

$\tt{: \implies x = \cancel{\dfrac{70}{10} }}$

$\bf{: \implies x = 7}$

$\bf{: \implies \red{\dfrac{x}{y} = \dfrac{7}{8} }}$

║Hence, the fraction x/y is 7/8.║