Question

if 2 is added to the numerator of a fraction it became 1 upon 2 and and if 1 is subtracted from the denominator it became one third find the fraction.​

Answer 1

the fraction be x/y

Given that

x+2/y =1/2 -----> equ i

x/y-1 =1/3 -----> equ ii

From i and ii

2(x+2) =1(y) -------> equ i

3(x) =1(y-1) -------> equ ii

=> 2x+4=y

3x=y-1

Subtract i and ii. we get

2x - y = -4

3x - y = -1

(-) (+) = (+)

______________

-x = -3

_____________

=> x=3

subtitute x=3 in equ i. we get

2(3+2)=y

=> 2(5) =y

=> y=10

Therefore the value of x and y are 3 and 10 respectively