if √2 is irrational prove that 3+5√2 is irrational
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Given :
√2 is Irrational number.
To prove :
3 + 5√2 is Irrational number.
Proof :
Let's us assume that 3 + 5√2 is a rational number .
Thus ,
3 + 5√2 = p/q , where p and q are integers and q ≠ 0 .
Now,
=> 3 + 5√2 = p/q
=> 5√2 = p/q - 3
=> 5√2 = (p - 3q)/q
=> √2 = (p - 3q)/5q -----(1)
If p/q is Rational then p/q - 3 is Rational.
If p/q - 3 is Rational then (p-3q)/q is Rational.
If (p-3q)/q is Rational then (p-3q)/5q is Rational.
If (p-3q)/5q is Rational then √2 is Rational.
{ using eq-(1) }
From eq-(1) , we get that √2 is Rational which contradicts the fact that √2 is an irrational number.
This, Our assumption is wrong and hence (3 + 5√2) is an irrational number.
Hence proved .
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