If 2 is one of the zero of the polynomial of 2x² – 3x + 1, then find another zero.
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Questions should be:
- If 1/2 is one of the zero of the polynomial of 2x² – 3x + 1, then find another zero.
ANSWER:
- Other zero = 1.
GIVEN:
- P(x) = 2x²-3x+1
- One zero = 2.
TO FIND:
- Zeros of the above polynomial.
SOLUTION:
=> 2x²-3x+1 = 0
=> 2x²-2x-x+1 = 0
=> (2x²-2x)+(-x+1) = 0
=> 2x(x-1)-1(x-1) = 0
=> (x-1)(2x-1) = 0
Either 2x-1 = 0
=> 2x = 1
=> x = 1/2
Either x-1 = 0
=> x = 1
NOTE:
Some important formulas:
(a+b)² = a²+b²+2ab
(a-b)² = a²+b²-2ab
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
(a+b)² = (a-b)²+4ab
(a-b)² = (a+b)²-4ab
Answered by
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Answer:
We can use factarisation method
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