If -2 is one of the zeroes of the polynomial
x - 4x2 - ax + 10, then find the remaining two
zeroes of the polynomial.
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x-4x^2-ax+10=0
put x=-2
(-2)-4(-2)^2-a(-2)+10=0
-2-16+2a+10=0
2a=8
a=4
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