Math, asked by pritamadhikarioffici, 8 months ago

if 2 is root of the quadratic equal x^2-mx+4=0

Answers

Answered by poorvasrij
1

Answer:

m=4

Step-by-step explanation:

P(x) = x^2-mx+4 =0

P(2)= 2^2-2m+4=0

=4-2m+4=0

8=2m

m=8/2

m=4

Answered by deepakPGDV
3

\huge\bf\mathfrak\green{An}\red{sw}\blue{er} \: is \: 4\huge\bf\green{Given \: that,} \\ x = 2 \\ The \:  given  \: equation \: is \\  {x}^{2}  - mx + 4 = 0 \\ By \: substituting  \\ \: the \: value \: of \: "x"  \: we \:  get \\  {(2)}^{2}  - m(2) + 4 = 0 \\ 4 - 2m + 4 = 0 \\ 8 - 2m = 0 \\ 2m = 8 \\ There \:  fore,m =  \frac{8}{2}  = 4

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