Question

If 2 is subtracted from 3 times the square of a positive number the result is 5 times the number find the numbers

Answer 1

Answer:

Step-by-step explanation:

represents “the number”

3x-11=(x-5)^2 [The question restated in equation form]

3x-11=x^2–5x-5x+25

3x-11–25=x^2–10x

-36=x^2–10x-3x

0=x^2–13x+36

[next substitute values: ax^2+bx+c=0]

[into quadratic formula: x=(-b[+-]sqr(b^2-4ac))/2a]

x=(-(-13)[+-]sqr(-13^2–4*1*36))/2*1

x=(13+sqr(169–144))/2 & (13-sqr(169–144))/2

x=(13+sqr(25))/2 & (13-sqr(25))/2

x=(13+5)/2 & (13–5)/2

x=18/2 & 8/2

x=9 & 4

The set of numbers that satisfy the conditions is [4,6].