if 2 is subtracted from the numerator and 1 is added to denominator the fraction becomes 1 upon 2 but 14 is added to the numerator and 3 subtracted from the denominator it becomes n3 upon 2 find the factor.
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let the numerator even x and denominator be y
a/q
x-2/y+1=1
x-2=y+1,(by cross multiplication)
x-y=-3. (1)
second case
x+14/y-3=3
x+14=3y-9(by cross multiplication)
x-3y=-23. (2)
equate 1&2
x-y=-3
x-3y=-23(by elimination method)
2y=20
y=10
put in 1 equation
x-(-10)=-3
x+10=-3
x=-13
kanhaiya494:
it's 4
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