Question

if 2 is the polynomial p(x)= 4x^2+2x-5a one is zero then the find value of a

Answer 1

Hey mate,

Your answer is-

$p(x) \: = \: 4 x^2+2x-5a \\ p(2) \: = \: 4x^2+2x-5a \: = \: 0 \\ = > 4( {2}^{2} ) + 2(2) - 5a = 0 \\ = > 16 + 4 - 5a = 0 \\ = > - 5a = - 20 \\ = > a = 4$


#KEVIN

I hope it will help you.

Answer 2

The given equation is ,

p(x)= $4x^{2} + 2 x - 5a$

As one of the zeroes of polynomial is zero, so put x=0 in above equation

p(0)= 4×0² + 2×0 -5 a

 = 0-5 a

 = - 5 a

As if x is the root of a polynomial f(x) then ,f(x)=0.

→ - 5 a = 0

→ a = 0/-5 = 0

So, the value of a is zero.