Question

if 2 is the root of equation x2+bx+12=0 find value of b

Answer 1

Answer:

The value of b=-8

Step-by-step explanation:

Given : If 2 is the root of equation $x^2+bx+12=0$

To find : The value of b?

Solution :

In the quadratic equation root is the term which satisfy the equation.

If 2 is the root of the given equation the it satisfy the equation.

So, Substitute x=2 in the given equation,

$x^2+bx+12=0$

$2^2+b(2)+12=0$

$4+2b+12=0$

$2b+16=0$

$2b=-16$

$b=-\frac{16}{2}$

$b=-8$

Therefore, The value of b=-8.

Answer 2

Answer:

We will get the value of b is -8.

Step-by-step explanation:

• As per the question we have to evaluate the given data.

              Given data:- x=2 and $x^{2} +bx+12=0.$

              To find:- Value of b.

              Solution:-

• Here we will use the transposition method.

• Transposition is one of the linear equations.

• To solve the transposition method we will Identify the variables and constants.

• Then we Simplify the equation in LHS and RHS.

• Now Simplify the equation using arithmetic operations.

           $\begin{array}{l}=>x^{2}+b x+12=0 \\=>2^{2}+b(2)+12=0 \\=>4+2 b+12=0 \\=>2 b+16=0 \\=>2 b=-16 \\=>b=-\frac{16}{2} \\=>b=-8\end{array}$