Question

if 2 is the root of the equation x² +6x+12=0 and
the equation x² + 6x+q=0 has equal roots find
q​

Answer 1

Step-by-step explanation:

Given equation x

2

+bx+12=0

one root is 2

So, put x=2

4+2b+12=0

2b=−16

b=−8

Now roots of equation x

2

+bx+q=0 are equal

So, D=0

b

2

−4q=0

(−8)

2

−4q=0

4q=64⇒q=16

Answer 2

Answer:

q= -16.

Step-by-step explanation:

substitute 2 in x² + 6x+q=0

= (2) ^2 + 6(2) + q = 0. = 4+12+q= 0.

q= -16.

hope this helps you...