if 2 is the root of the quadratic equation 3 X square + px minus 8 is equal to zero and the quadratic equation 4 x square - 2 pX + K is equal to zero has equal roots find the value of k
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One root is 2
.:f(x)=3x^2+px-8
f(2)=3(2)^2+2p-8
0=12+2p-8
-2p=4
.:p=(-2)
F(x)=4x^2-2px+k
As roots are equal
.: D=0
D=b^2-4ac
0=(2p)^2-4(4k)
0=4p^2-16k
As p=-2
.: 0=4(-2)^2-16k
0=16-16k
16k=16
.:k=1
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