if 2 is the root of the quadratic equation 3x ^2+px-8.and the quadratic equation 4x^2-2px+k has equal roots. find the value of k
Answers
Answered by
12
The value of k is 1. Where the value of p be (-2).
Sejal02:
Where is the solution
Answered by
35
Answer:
Step-by-step explanation:
Solution :-
Given, 2 is a root of the equation, 3x² + px - 8 = 0
Putting x = 2 in 3x² + px - 8 = 0, we get
⇒ 12 + 2p - 8 = 0
⇒ p = - 2
Given, 4x² - 2px + k = 0 has equal roots,
and 4x² + 4x + k = 0 has equal roots,
D = b² - 4ac = 0
⇒ (4)² - 4(4)(k) = 0
⇒ 16 - 16k = 0
⇒ 16k = 16
⇒ k = 16/16
⇒ k = 1
Hence, the required value of k is 1.
Similar questions