Math, asked by shivani1232, 1 year ago

if 2 is the root of the quadratic equation 3x ^2+px-8.and the quadratic equation 4x^2-2px+k has equal roots. find the value of k

Answers

Answered by rajdeep740
12
The value of k is 1. Where the value of p be (-2).

Sejal02: Where is the solution
shivani1232: thanks.. i got it
Answered by VishalSharma01
35

Answer:

Step-by-step explanation:

Solution :-

Given, 2 is a root of the equation, 3x² + px - 8 = 0

Putting x = 2 in 3x² + px - 8 = 0, we get

⇒ 12 + 2p - 8 = 0

p = - 2

Given, 4x² - 2px + k = 0 has equal roots,

and 4x² + 4x + k = 0 has equal roots,

D = b² - 4ac = 0

⇒ (4)² - 4(4)(k) = 0

⇒ 16 - 16k = 0

⇒ 16k = 16

⇒ k = 16/16

k = 1

Hence, the required value of k is 1.

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