Math, asked by anithaan1415m, 2 months ago

If 2 is the root of the quadratic equations 3 x2+ px -8 = 0 and 4x2 - 2 p x +q= 0 . Find the
value of q.
10​

Answers

Answered by amitsharma777222999
3

Step-by-step explanation:

3(2)^2+p(2)-8=0

2p+12-8=0

2p=-4

p=-2

put in second equation

4(2)^2-2(-2)+q=0

16+4+q=0

q=-20

Answered by Enrique001
8

Answer:

Since x=2,

3 {x}^{2}  + px - 8 =0 \\  =  > 3 \times 4 + p \times 2 - 8 = 0 \\  =  > 12 + 2p - 8 = 0 \\  =  > 2p + 4 = 0 \\  =  > 2p =  - 4 \\  =  > p =  - \frac{ - 4}{2}  =  - 2

Therefore,

4 {x}^{2}  - 2px + q = 0 \\  =  > 4 \times 4 - 2 \times(  - 2) \times \: 2 + q = 0  \\  =  > 16  + 8 + q = 0 \\  =  > 24 + q = 0 \\  =  > q =  - 24

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