Question

If 2 is the root of x^2+bx+12=0 then find the value of b and find the other root

Answer 1

Answer:

given that x²+bx+12=0

and 2 is a root

Step-by-step explanation:

put x=2 in the above equation  {∵2 is a root of the equation}

⇒[2]²+b[2]+12=0

⇒4+2b+12=0

⇒16+2b=0

⇒2b=-16

⇒b=-16/2

⇒b=-8

putting b value in equation

⇒x²-8x+12=0 be the required equation

lets find it roots by splitting method

⇒x²-2x-6x+12=0

⇒x[x-2]-6[x-2]=0

⇒[x-6] [x-2]=0

⇒x-6=0 and x-2=0

∴x=6 and x=2