If 2 is the zero of polynomial f(x)=ax^2-3(a-1)x-1 find the value of a
Answers
Answered by
1
Answer:
put the value 2in the place of x and solve it
Answered by
2
Answer:
Given,
f(x) = ax² - 3(a-1)x - 1
2 us zero of the polynomial...
So, f(2) = 0
=> f(2) = a×2² - 3(a-1)×2 - 1
=> 4a -6(a-1) - 1 =0
=> 4a - 6a + 6 - 1 = 0
=> - 2a + 5 =0
=> - 2a = -5
=> a = 5/2 ans......
Similar questions