Question

if 2 is the zero of the polynomial p(x)= kx^2-3(k-1)x-1 then the value of k is

Answer 1

Step-by-step explanation:

k(2²) - 3(k-1)2 -1

= 4k -6k+6-1

-2k+5=0

-2k= -5

k= 5/2

Answer 2

Answer:

4/11

Step-by-step explanation:

Given info : 2 is a zero of polynomial P(x) = kx² + (3k - 2)x + k.

To find : The value of k.

solution : if 2 is a zero of polynomial P(x) = kx² + (3k - 2)x + k, 2 must satisfy the equation kx² + (3k -2)x + k = 0.

i.e., k(2)² + (3k - 2)(2) + k = 0

⇒4k + 6k - 4 + k = 0

⇒11k - 4 = 0

⇒k = 4/11

Therefore the value of k is 4/11.

also read similar questions : if k is zero of the polynomial g(x)= kx^2-x, then find the value of k