Question

if 2 is the zero of the polynomial p(X)=kx^2+(3x-2) X+k then find the value​

Answer 1

Step-by-step explanation:

p(2)=4k+(6-2)2+k=0

→4k+8+k=0

→5k+8=0

→5k=-8

→k=-8/5

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Answer 2

Step-by-step explanation:

Given:-

2 is the zero of the polynomial p (x)=${kx}^{2}+(3x-2)x+k$

To find:-

value of k

Solution :-

If 2 is the zero of the polynomial

${:}\longrightarrow$$p (x)=0$

${:}\longrightarrow$$p (2)={kx}^{2}+(3x-2)x+k=0$

${:}\longrightarrow$$k×{2}^{2}+(3×2-2)2+k=0$

${:}\longrightarrow$$4k+(6-2)2+k=0$

${:}\longrightarrow$$4k+8+k=0$

${:}\longrightarrow$$5k+8=0$

${:}\longrightarrow$$5k=(-8)$

${:}\longrightarrow$${\underline{\boxed{\bf {k={\frac {(-8)}{5}}}}}}$.