Math, asked by vin63, 1 year ago

if 2 is the zero of the polynomial p(x)=kx^ +(3k - 2)x + k then find the value of k

Answers

Answered by preeti09
22

kx^2+(3K-2)x+k

k2^2+(3k-2)2+k=0

4k+6k-4+k=0

11k-4=0

11k=4

k=4/11

Answered by KritikaSingh14
8
p ( 2 ) = k ( 2 ) + ( 3k - 2 ) 2 + k

2k + 6k - 4 + k = 0

9k - 4 = 0

9k = 4

k = 4 / 9


Hope it helps.....

preeti09: ur logic is correct..but ur ans does not satisfy the polynomials...becoz according to ur ans this is neither linear polynomial nor quadratic polynomial
KritikaSingh14: hii
ÏnsÂnëYüvîBrø: hii
KritikaSingh14: fine n u
ÏnsÂnëYüvîBrø: kaisa ho donu
ÏnsÂnëYüvîBrø: ?!?
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