Question

if 2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1 than find the value of a​

Answer 1

Answer:

a(2)²-3(a-1)2-1=0

4a-6a+6-1=0

-2a+5=0

-2a=-5

-a=-5/2

a=5/2

Answer 2

Answer:

$\huge\underbrace\purple{\dag Question \dag}$

if 2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1 than find the value of a

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2 is zeros of polynomials f(x)=ax^2-3(a-1)x-1

$f(2) = a( {2})^{2} - 3(a - 1)2 - 1 = 0 \\ 4a - 6a + 6 - 1 = 0 \\ - 2a + 5= 0 \\ - 2a = 0 - 5 \\ - 2a= - 5 \\ a = \frac{ - 5}{ - 2} \\ a = \boxed{ \frac{5}{2} }$

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