Question

if 2 litres of n2 is mixed with 2 litres of h2 calculate the volume of nh3 formed

Answer 1

Answer: 1.32 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}$

$\text{Number of moles of nitrogen}=\frac{2L}{22.4L}=0.089 moles$

$\text{Number of moles of hydrogen}=\frac{2L}{22.4L}=0.089moles$

$N_2+3H_2\rightarrow 2NH_3$

Now 3 moles of $H_2$ combine with 1 mole of $N_2$ to give 2 moles of $NH_3$

Thus 0.089 moles of $H_2$ will combine with=$\frac{1}{3}\times 0.089=0.029$ moles of $N_2$

Thus $H_2$ acts as limiting reagent as it limits the formation of product.

3 moles of $H_2$ give 2 moles of $NH_3$

0.089 moles of $H_2$ will give=$\frac{2}{3}\times 0.089=0.059$ moles of $NH_3$

Volume of $NH_3=moles\times Molar volume=0.059\times 22.4=1.32L$

Answer 2

Answer:

Answer is 1.33 L

Explanation:

Hope this answer helps you...!!!