If 2 log a + 3 log b−2 = 0, then prove that a2b3= 100.
Answers
Answered by
2
Answer:
Given that,
2
3
loga+
3
2
logb−1=0
log(a)
2
3
+log(b)
3
2
=1
log(a)
2
3
(b)
3
2
=1
log(a)
6
9
(b)
6
4
=1
(a
9
b
4
)
6
1
=10
1
=10
∴a
9
b
4
=10
6
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Answered by
0
Answer:
she give correct answer
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