If 2 log (x + 3) = log 81, then the value of ‘x’ is
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ANSWER
FORMULA
n log (x) = log (x) ^n
SOLUTION
2 log(x+3) = log 81
log (x+3) ^2 = log 81
take antilog to remove log
(x+3)^2 = 81
x^2 +6x +8 -81 = 0
x^2 +6x -72 = 0
x^2 +12 x -6x -72 = 0
x(x+12) -6(x+12) =0
(x-6) (x+12) =0
solve this equation by quadratic formula
we get
x = 6
x = -12 but x = -12 is not possible because if we put x = -3 in log then it become negative as
-12+3 = -9
and log for negative numbers is not defined
so
x = 6
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