Question

if 2^m+n / 2^n-m = 16 & a = 2^1/10 then find the value of a ^3m

Answer 1

Step-by-step explanation:

2^m+n × 2^ m-n = 2⁴

2^(m+n+m-n) = 2⁴

2^ (2m) = 2⁴

when base are same powers will be equal in equation

2m = 4

m = 2

now a^3m

2^{(1/10)×3×2}

2^ 6/10

2^ 3/5

Answer 2

Hope it helps you

If it is wrong sorry ...