If 2 men and 3 boy can do a piece of work in 10 days while 3 men and 2 boy can do the same work in 8 day .in how many days can 2 men and 1 boy do the work ?
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total work=lcm of 10 & 8 days =40
2 m+3 b=40/10=4
3 m+2b=40/8=5
6m+9b=12
6m+4b=10
5b=2
1 boy ka 1 day work=2/5 units
2 m+3 ×2/5=4
2 m ka 1 day work
=4-6/5=14/5
2 m +1 boy ka 1 day work=14/5+2/5=16/5 units
total work =40 units
no. of days=40/(16/5)=200/16=50/4=12½ days
2 m+3 b=40/10=4
3 m+2b=40/8=5
6m+9b=12
6m+4b=10
5b=2
1 boy ka 1 day work=2/5 units
2 m+3 ×2/5=4
2 m ka 1 day work
=4-6/5=14/5
2 m +1 boy ka 1 day work=14/5+2/5=16/5 units
total work =40 units
no. of days=40/(16/5)=200/16=50/4=12½ days
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