Question

If 2 men and 7 boys do a piece of
work in 14 days while 3 men and 8
boys do the same piece of work in
11 days, then in how many days
will 8 men and 6 boys do thrice of
that work?
(A) 11 (B) 21 (C) 31 (D) 41​

Answer 1

Answer:

let one man one day work be x

let one boy one day work be y

28x+98y=1

33x+88y=1

28x+98y=33x+88y

10y=5x

x=2y

which means one man is equal to 2 boys

so we can conclude that 11 boys can do a work in 14 days

so one boy can do a work in 14×11 days

one day work of one boy=1/(14×11)

so according to question 22 boys one day work will be 1/7

so let the work be completed in x days

so work done by 22 boys in x days=x/7

x/7=3

x=21

woooohoooooooo got it.......