Question

If 2 ml of acetone is present in 45 ml of its aqueous solution ,calculate the concentration of solution

Answer 1

Answer:

4.44%

Explanation:

Concentration of a solution= volume of solution/ volume of solute

= (2/45)×100 = 4.44%

Answer 2

Answer:

Concept:

Water in the liquid state serves as the solvent in an aqueous solution. In other words, water molecules surround and integrate solute (dissolved) ions and molecules into their web of bonds. The dissolved species subsequently dispersed across the river.

Explanation:

Volume of solute (acetone) = 2 mL

Volume of solution (solute+solvent) = 45 mL

Concentration of solution = $\frac{\text { Volume of solute }}{\text { Volume of solution }} \times 100$

Concentration of solution   $=\frac{2}{45} \times 100$

                                         

Concentration of solution   $=4.44 \%$

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