Question

If 2 moles of NaOH is dissolve in 420 gram of water then the mass percentage of NaOH in the solution is

Answer 1

Given Data:

Mass of solute - 2 Moles of NaOH 1 mole of NaOH is 39.99 grams,

so 2 moles of NaOH is 79.99 grams

mass of Solution - 420 grams

Mass percentage of NaOH = $\frac{\text {mass in grams of solute}}{\text {mass in grams of solution}} \times 100$

=  $\frac{79.99}{420} \times 100$

= 19%

The Mass percentage of NaOH in the solution is 19%.

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Answer 2

$\huge \tt 19\%$