Question

If 2^n^2-2^n+1+2^n=c×2^n,find the value of c
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Answer 1

2^(n+2)=2^n*4

2^(n+1)=2^n*2

So

By simplifying it

2^n*4-2^n*2=C*2^n

Taking the 2^n common from the LHS, we get is now

2^n(4-2)=C*2^n

2*2^n=C*2^n

From comparison of LHS & RHS

We find the value of: C=2

Answer 2

Step-by-step explanation:

2^(n+2)=2^n*4

2^(n+1)=2^n*2

So

By simplifying it

2^n*4-2^n*2=C*2^n

Taking the 2^n common from the LHS, we get is now

2^n(4-2)=C*2^n

2*2^n=C*2^n

From comparison of LHS & RHS

We find the value of: C=2