Question

if (2^n*3^m* 8^3*90) / 15*16^2 *9^4 =48​

Answer 1

Answer:

2,7

Step-by-step explanation:

2^n*3^m*8*8*8*90/15*16*16*9*9*9*9 = 48

after cancelling ,

2^n*3^m= 4*3*9*9*9

2^n*3^m = 2^2*3^7

(n,m)= (2,7)

Answer 2

Step-by-step explanation:

• So we get on simplification.
•       2^n x 3^m x 8^3 x 90 / 15 x 16^2 x 9^4 = 48
•       2^n x 3^m x (2^3)^3 x 2 x 3^2 x 5 / 3 x 5 x (2^4)^2 x (3^2)^4 = 2^4 x 3
•      2^n x 3^m x 2^9 x 2 x 3^2 x 5 /  3 x 5 x (2^4)^2 x (3^2)^4 x 2^4 x 3 = 1
•     2^n x 3^m x 2^9 x 2 x 3^2 x 5 / 3 x 5 x 2^8 x 3^8 x 2^4 x 3 = 1
•     2^n x 3^m x 2^10 / 2^12 x 3^8 (by using law of exponents a^m x a^n = a^m + n  
•     2^n x 3^m x 2^-2 x 3^-8 = 1    
•     Now n - 2 = 0 and m - 8 = 0
•          n = 2 and m = 8

Reference link will be

https://brainly.in/question/45209779