Question

If 2^n=64 then find the value of 2^3n-1​

Answer 1

$\tt\huge\red{Given}$

$\sf {2}^{n} = 64$

$\huge\tt\red{To \: \: find }$

$\sf {2}^{3n - 1} =?$

$\huge\tt\red{Solution}$

$\bf \implies {2}^{n} = 64$

$\bf\implies {2}^{n} = {2}^{6}$

$\bf\implies\not{2} {}^{n} = \not{2} {}^{6}$

$\bf\implies \: n = 6$

Now,

${}$

$\bf = {2}^{3n - 1}$

Putting the value of n we will get -

$\bf = {2}^{3 \times 6 - 1}$

$\bf = {2}^{18 - 1}$

$\bf = {2}^{17}$

$\bf = 131072$