if 2% of the main current is to be passed through the galvanometer of resisance g, the resistance of shunt required iss?
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S= GIg/(I-Ig)
Ig = 2%(I)=I/50
Therefore S = G(I/50)/(I-I/50)
S= G(I/50)/(49I/50ohms)
S=G/49.
hope it helps you
Ig = 2%(I)=I/50
Therefore S = G(I/50)/(I-I/50)
S= G(I/50)/(49I/50ohms)
S=G/49.
hope it helps you
Anonymous:
no problem
understood
thanks again for ur help
4v
thanks for giving me ur precious time
hm
ok bye bye
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