Question

If 2 ohm, 6ohm,12ohm are connected in a parallel connection find the effective resistance

Answer 1

Explanation:

ANSWER:-

Given-:

2 ohm, 6 ohm and 12 ohm in parallel

Effective resistance =?

We know that

If we take equivalent resistance as x,

$\frac{1}{x} = \frac{1}{x1} + \frac{1}{x2} + \frac{1}{x3}$

• x is Total equivalent resistance
• x1 , x2 and X3 are other resistances

So, placing them:-

$\frac{1}{x1} = \frac{1}{2} + \frac{1}{6} + \frac{1}{12}$

Taking LCM as 12,

$\frac{6 + 2 + 1}{12} = \frac{1}{x}$

$\frac{9}{12} = \frac{1}{x}$

$x = \frac{4}{3} \Omega$

So effective resistance is 4/3 ohm.

Things To Note:-

• Always reciprocal the resultant value in parallel combination
• Simple addition is followed in series combination
• SI unit of resistance is Ohm
• Resistance is property to resist the flow of current .

Answer 2

Answer:we know that they are in parallel connection,

1/Req=1/R1+1/R2+1/R3

1/Req=1/2+1/6+1/12

1/Req=6+2+1/12

1/Req=9/12

1/Req=3/4

Req=4/3ohms

So equivalent resistance=4/3ohms

Explanation:

Hope it helps.....