if 2 opposite sides of cyclic quadrilateral are equal prove that the other two sides are parallel
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Let ABCD be quadrilateral with ab||cd
Join be.
In triangle abd and CBD,
Angle abd=angle cdb(alternate angles)
Anglecbd=angle adb(alternate angles)
Bd=bd(common)
Abd=~CBD by asa test
Ad=BC by cpct
Since ad =bc ABCD is a isosceles trapezium
Angle d= angle c - - - - - - (1)
Join ac.
In triangle adc and bcd
Cd=cd(common)
Angle d =angle c(from 1)
Ad =bc(proved above)
Triangle adc=~bcd. by sas test
Ac=bd. by cpct
HOPE THIS HELPS YOU!!! ❤❤
Let ABCD be quadrilateral with ab||cd
Join be.
In triangle abd and CBD,
Angle abd=angle cdb(alternate angles)
Anglecbd=angle adb(alternate angles)
Bd=bd(common)
Abd=~CBD by asa test
Ad=BC by cpct
Since ad =bc ABCD is a isosceles trapezium
Angle d= angle c - - - - - - (1)
Join ac.
In triangle adc and bcd
Cd=cd(common)
Angle d =angle c(from 1)
Ad =bc(proved above)
Triangle adc=~bcd. by sas test
Ac=bd. by cpct
HOPE THIS HELPS YOU!!! ❤❤
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